2x-x*5x+4x=5x^2+4x

Solution for 2x-x*5x+4x=5x^2+4x equation:

2x-x*5x+4x=5x^2+4x

We move all terms to the left:

2x-x*5x+4x-(5x^2+4x)=0

We add all the numbers together, and all the variables

6x-x*5x-(5x^2+4x)=0

Wy multiply elements

-5x^2+6x-(5x^2+4x)=0

We get rid of parentheses

-5x^2-5x^2+6x-4x=0

We add all the numbers together, and all the variables

-10x^2+2x=0

a = -10; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-10)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-10}=\frac{-4}{-20}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-10}=\frac{0}{-20}
=0
$